A) \[<0\]
B) \[>0\]
C) \[\le 0\]
D) none of these
Correct Answer: A
Solution :
From figure it is clear that if \[a>0,\]and \[f(-1)<0\] and \[f(1)<0\]and if \[a<0,f(-1)>0\]and \[f(1)>0.\] In both cases, \[af(-1)<0\]and \[af(1)<0.\] \[\Rightarrow \]\[a(a-b+c)<0\]and \[a(a+b+c)<0\] On dividing by \[{{a}^{2}},\] \[\Rightarrow \] \[1-\frac{b}{a}+\frac{c}{a}<0\] and \[1+\frac{b}{a}+\frac{c}{a}<0\] Combining both equations, we get \[1\pm \frac{b}{a}+\frac{c}{a}<0\] \[\Rightarrow \] \[1+\left| \frac{b}{a} \right|+\frac{c}{a}<0\]You need to login to perform this action.
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