A) \[\lambda =\frac{h}{mE}\]
B) \[\lambda =\frac{\sqrt{2mE}}{h}\]
C) \[\lambda =\frac{h}{2mE}\]
D) \[\lambda =\frac{h}{\sqrt{2mE}}\]
Correct Answer: D
Solution :
de-Broglie wavelength of a body moving with velocity \[v\]is given by \[\lambda =\frac{h}{mv}\] ?(i) where h is Plancks constant. The kinetic energy of the body moving with velocity \[v\] is \[E=\frac{1}{2}m{{v}^{2}}\] or \[mv=\sqrt{2Em}\] ?(ii) Combining Eqs. (i) and (ii), we have \[\lambda =\frac{h}{\sqrt{2mE}}\]
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