A) 41.4%
B) 50%
C) 82.8%
D) 100%
Correct Answer: A
Solution :
The velocity with which satellite is orbiting around the earth is the orbital velocity \[({{v}_{o}})\] and that required to escape out of gravitational pull of earth is the escape velocity \[({{v}_{es}}).\] \[{{v}_{es}}=\sqrt{2gR}\]and \[{{v}_{o}}=\sqrt{gR}\] \[\therefore \]Increase in velocity required \[=\frac{{{v}_{es}}-{{v}_{o}}}{{{v}_{o}}}=\frac{\sqrt{2gR}-\sqrt{gR}}{\sqrt{gR}}\] \[=\sqrt{2}-1\] \[=0.414\] Percent increase in velocity required \[=0.414\times 100\] \[=41.4%\]You need to login to perform this action.
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