A) \[\frac{18.03}{17.03}\]
B) \[\frac{17.03}{18.03}\]
C) \[\frac{18.03}{19.83}\]
D) \[\frac{15.03}{17.83}\]
Correct Answer: C
Solution :
Weight of wax in air, \[{{W}_{a}}=18.13g\] Weight of metal piece in water \[=17.03g\] Weight of metal piece and wax in water \[=15.23g\] Weight of wax in water \[{{W}_{w}}=15.23-17.03=-1.8g\] Therefore, specific gravity of wax \[\text{=}\,\,\frac{\text{weight}\,\text{of}\,\text{wax}\,\text{in}\,\text{air}}{\text{weight}\,\text{of}\,\text{wax}\,\text{in}\,\text{air-weight}\,\text{of}\,\text{wax}\,\text{in}\,\text{water}}\] \[=\frac{18.03}{18.03-(-1.8)}\] \[=\frac{18.03}{19.83}\]
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