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BCECE Engineering BCECE Engineering Solved Paper-2002

  • question_answer
    A compound contains 38.8% C, 16% H and 45.2% N. The empirical formula of the compound will be:

    A) \[C{{H}_{5}}N\]

    B)        \[{{C}_{2}}{{H}_{5}}N\]

    C) \[CHN\]               

    D)        \[C{{H}_{10}}{{N}_{2}}\]

    Correct Answer: A

    Solution :

    Element % Relative no. of atoms Simple ratio
    C 38.8 \[38.8/12=3.2\] \[3.2/3.2=1\]
    H \[16.0\] \[16/1=16.0\] \[16.0/3.2=5\]
    N \[45.2\] \[45.2/14=3.2\] \[3.2/3.2=1\]
                    \[\therefore \] Empirical formula \[=C{{H}_{5}}N\]


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