A) 500 \[\text{A}\]
B) 0.25\[\text{A}\]
C) 0.01 \[\text{A}\]
D) 100 \[\text{A}\]
Correct Answer: A
Solution :
From the relation \[V=i\,R\] We have, \[V=0.01\,volt,\,R=1000\,\Omega \] \[\therefore \] \[\Delta {{i}_{B}}=\frac{V}{R}=\frac{0.01}{1000}={{10}^{-5}}A\] Also from definition of AC current gain, \[\beta \]is the ratio of change in collector current to change in base current at a constant collector to emitter voltage. That is \[\beta =\frac{\Delta {{i}_{C}}}{\Delta {{i}_{B}}}\] \[\Rightarrow \] \[\Delta {{i}_{C}}=\beta \Delta {{i}_{B}}\]\[=50\times {{10}^{-5}}=500\,\mu A\]
You need to login to perform this action.
You will be redirected in
3 sec
