A) \[1.0\times {{10}^{-4}}\] rad
B) \[0.5\times {{10}^{-4}}\] rad
C) \[0.15\times {{10}^{-3}}\] rad
D) \[1.5\times {{10}^{-3}}\] rad
Correct Answer: D
Solution :
Angle of diffraction for the secondary maxima \[\theta =\frac{3}{2}\times \frac{\lambda }{a}\] \[=\frac{3}{2}\times \frac{4000\times {{10}^{-10}}}{0.4\times {{10}^{-3}}}\] \[=\frac{30}{2}\times {{10}^{-4}}\] \[=15\times {{10}^{-4}}\] \[=1.5\times {{10}^{-3}}rad\]You need to login to perform this action.
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