A) 3.5eV
B) 2.6eV
C) 2.2eV
D) 1.3eV
Correct Answer: D
Solution :
Given, \[\lambda =350\,nm=350\times {{10}^{-7}}m\] Intensity \[=1.00\,\,\omega /{{m}^{2}}\] work function W = 2.2 eV Energy of the photon \[=\frac{hc}{\lambda }\] \[=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{350\times {{10}^{8}}}\] \[=3.5\,eV\] \[{{K}_{\max }}=E-W\] \[=(3.5-2.2)\,eV\] \[=1.3\,eV\]You need to login to perform this action.
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