question_answer

What type of hybridisation is involved in the metal ion of \[{{[Ni{{({{H}_{2}}O)}_{6}}]}^{2+}}\] complex?

A)  \[{{d}^{2}}s{{p}^{3}}\]                                 

B)  \[s{{p}^{3}}{{d}^{2}}\]

C)  \[s{{p}^{3}}\]                                   

D)  \[ds{{p}^{2}}\]

Correct Answer: B

Solution :

                In \[{{[Ni{{({{H}_{2}}O)}_{6}}]}^{2+}}\] complex ion Ni is in +2 oxidation state, it has electronic configuration \[3{{d}^{8}}\]. Orbitais of \[N{{i}^{2+}}\] ions \[{{H}_{2}}O\] is a weak field ligand. So, pairing of electrons in d- orbitais does not occur. The complex \[{{[Ni{{({{H}_{2}}O)}_{6}}]}^{2+}}\] involves the outer 4d-orbitals for hybridisation\[(s{{p}^{3}}{{d}^{2}})\]. It is outer orbital complex. \[s{{p}^{3}}{{d}^{2}}\] hybridised orbitais of \[N{{i}^{2+}}\]                 \[{{[Ni{{({{H}_{2}}O)}_{6}}]}^{2+}}\]