A) \[\alpha \]-elimination
B) \[\beta \]-elimination
C) Hofmann elimination
D) None of the above
Correct Answer: B
Solution :
\[C{{H}_{3}}-\overset{\begin{smallmatrix} H \\ \left| \beta \right. \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,}}\,-C-C{{H}_{3}}\xrightarrow[-{{H}_{2}}O,\,-KBr]{Alc.\,\,KOH}\] \[{{H}_{3}}C-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,=\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}\] The above reaction is an example of \[\beta \]-elimination.You need to login to perform this action.
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