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AMU Medical AMU Solved Paper-2012

  • question_answer
    A rod lies along the x-axis with one end at the origin and the other at \[x\to \infty \]o. it carries a uniform charge \[\lambda \,C/m\]. The electric field at the point \[x=-a\] on the axis will be

    A)  \[E=\frac{\lambda }{4\pi {{\varepsilon }_{0}}a}(-i)\]       

    B)  \[E=\frac{\lambda }{4\pi {{\varepsilon }_{0}}a}(i)\]

    C)  \[E=\frac{\lambda }{2\pi {{\varepsilon }_{0}}a}(-i)\]       

    D)  \[E=\frac{\lambda }{2\pi {{\varepsilon }_{0}}a}(i)\]

    Correct Answer: C

    Solution :

                     The electric field at the point \[x=-a\]    \[{{E}_{out}}=\frac{\lambda }{2\pi {{\varepsilon }_{0}}a}\,\,(-i)\]


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