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AMU Medical AMU Solved Paper-2010

  • question_answer
    The pH of a solution obtained by mixing equal volumes of \[\frac{N}{10}\] NaOH and \[\frac{N}{20}\] HCl is

    A)  13.4                                      

    B)  12.4

    C)  7.6                                        

    D)  1.6

    Correct Answer: B

    Solution :

                     Let the volume of NaOH used = V = volume of HCl used. Concentration of mixture \[[O{{H}^{-}}]\]                                                 \[v=\frac{0.1\,\,V-0.05\,V}{(V+V)}\] [\[\because \] Milliequivalent of NaOH is in excess.]                 \[v=\frac{V(0.1\,-0.05\,)}{2V}\]                 \[=\frac{0.05}{2}=0.025\]                 \[pOH=-\log [O{{H}^{-}}]=-\log (0.025)\]                                                 = 1.602 \[\therefore \]  pH = 14 - 1.602 = 12.4


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