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AMU Medical AMU Solved Paper-2010

  • question_answer
    A man, of mass 60 kg, is riding in a lift. The weight of the man, when the lift is accelerating upwards and downwards at 2 \[m{{s}^{-2}}\] are respectively \[\left( \text{taking g }=\text{ 1}0\text{ m}{{\text{s}}^{-\text{2}}} \right)\]

    A)  720 N and 480 N              

    B)  480 N and 720 N

    C)  600 N and 600 N              

    D)  None of these

    Correct Answer: A

    Solution :

                     When the lift is accelerating upwards with constant acceleration a, then Weight \[w=m(g+a)\]                 \[=60(10+2)=60\times 12=720\,N\] When the lift is accelerating downwards at the rate of a, then Weight \[w=m(g-a)\]                 \[=60(10-2)=60\times 8=480N\]


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