A) II, I, III
B) III, II, I
C) I, II, III
D) II, III, I
Correct Answer: D
Solution :
Nylon-66 is a fibre and has hydrogen bonding as intermolecular force. Buna-S is an elastomer and has weak van der Waals forces. Polythene is thermoplastic and has intermediate intermolecular forces (ie, stronger than elastomer but weaker than fibre). Thus, the order of intermolecular forces is \[\underset{\left( II \right)}{\mathop{Buna-S}}\,<\underset{\left( III \right)}{\mathop{polythene}}\,<\underset{\left( I \right)}{\mathop{Nylon-66}}\,\]
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