AMU Medical AMU Solved Paper-2009

  • question_answer
    Entropy changes for the process,\[{{H}_{2}}O(l)\xrightarrow{{}}{{H}_{2}}O(s)\]at normal pressure and 274 K are given below \[\Delta {{S}_{system}}=-22.13\,\Delta {{S}_{surr}}=+22.05\] The process is non-spontaneous because. (surr stands for surrounding and u stands for universe)

    A)  \[\Delta {{S}_{system}}\] is -ve

    B)  \[\Delta {{S}_{surr}}\] is + ve

    C)  \[\Delta {{S}_{u}}\] is -ve                            

    D)  \[\Delta {{S}_{system}}\ne \Delta {{S}_{surr}}\]

    Correct Answer: C

    Solution :

                     For spontaneous process, \[\Delta {{S}_{u}}\] must be positive. So, the process is non-spontaneous as \[\Delta {{S}_{u}}\] is -ve.


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