A) ABC
B) \[AB{{C}_{2}}\]
C) \[AB{{C}_{3}}\]
D) \[AB{{C}_{4}}\]
Correct Answer: C
Solution :
Number of atoms of A per unit cell \[=8\times \frac{1}{8}\] (at the corners) = 1 Number of atoms of B per unit cell = 1 (at the centre) = 1 Number of atoms of C per unit cell \[=12\times \frac{1}{4}\] (at the edge centre) = 3 So, the formula of the compound is\[AB{{C}_{3}}.\]
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