A) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{3}}<C{{H}_{3}}CHO>C{{H}_{3}}OC{{H}_{3}}\]\[<C{{H}_{3}}C{{H}_{2}}OH\]
B) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{3}}<C{{H}_{3}}CHO>C{{H}_{3}}OC{{H}_{3}}\]\[<C{{H}_{3}}C{{H}_{2}}OH\]
C) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{3}}>C{{H}_{3}}CHO>C{{H}_{3}}OC{{H}_{3}}\]\[<C{{H}_{3}}C{{H}_{2}}OH\]
D) \[C{{H}_{3}}C{{H}_{2}}OH<C{{H}_{3}}CHO<C{{H}_{3}}OC{{H}_{3}}\]\[<C{{H}_{3}}C{{H}_{2}}C{{H}_{3}}\]
Correct Answer: A
Solution :
\[C{{H}_{3}}C{{H}_{2}}OH\] has the highest boiling point among the given due to H-bonding. \[C{{H}_{3}}OC{{H}_{3}}\] has higher molecular weight than \[C{{H}_{3}}C{{H}_{2}}C{{H}_{3}}\] and thus, has the higher boiling point \[C{{H}_{3}}CHO\]. \[C{{H}_{3}}CHO\] has higher boiling point than alkane due to dipole-dipole interaction. Thus, the correct order of boiling point is \[C{{H}_{3}}C{{H}_{2}}C{{H}_{3}}<C{{H}_{3}}OC{{H}_{3}}<C{{H}_{3}}CHO\]\[<C{{H}_{3}}C{{H}_{2}}OH\]
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