A) 0.8 M
B) 0.6 M
C) 0.4 M
D) 0.2 M
Correct Answer: B
Solution :
Given, \[:{{M}_{1}}=0.5\,M,\,{{M}_{2}}=1M,\,\,{{V}_{1}}=800\,mL,\]\[\,{{V}_{2}}=200\,mL\] \[{{V}_{3}}={{V}_{1}}+{{V}_{2}}=800+200=1000\,\,mL\] \[{{M}_{1}}{{V}_{1}}+{{M}_{2}}{{V}_{2}}={{M}_{3}}{{V}_{3}}\] \[\Rightarrow \] \[0.5\times 800+1\times 200={{M}_{3}}\times 1000\] \[{{M}_{3}}=\frac{0.5\times 800+1\times 200}{1000}=\frac{600}{1000}=0.6\,M\]
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