AMU Medical AMU Solved Paper-2009

  • question_answer
    An element A decays into an element C by a two step process. \[A\to B{{+}_{2}}H{{e}^{4}}\] \[B\to C+2{{e}^{-}}\] Then

    A)  A and C are isobars

    B)  A and C are isotopes

    C)  A and B are isotopes

    D)  A and B are isobars

    Correct Answer: B

    Solution :

                     \[_{Z}{{A}^{A}}{{\xrightarrow{{}}}_{Z-2}}{{B}^{A-4}}{{+}_{2}}H{{e}^{4}}\] \[_{Z-2}{{A}^{A-4}}{{\xrightarrow{{}}}_{Z}}{{B}^{A-4}}+2\,e_{-1}^{0}\] A and C have the same atomic number but different mass numbers, therefore A and C are isotopes.


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