A) 589 nm
B) 443 nm
C) 333 nm
D) 221 nm
Correct Answer: B
Solution :
The refractive index of water with respect to air \[_{a}{{\mu }_{w}}=\frac{{{\mu }_{w}}}{{{\mu }_{a}}}\] \[=\frac{\mu {{\lambda }_{air}}}{v{{\lambda }_{water}}}\] \[\therefore \] \[\lambda \] in water \[=\frac{{{\lambda }_{air}}}{\mu }\] \[\Rightarrow \] \[\lambda \] in water \[=\frac{589}{1.33}nm\] \[\Rightarrow \] \[\lambda \] in water = 443 nm
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