A) \[\text{5}.0\text{x1}{{0}^{-\text{2}}}\text{ }\Omega .\]
B) \[\text{4}.\text{4}\times \text{1}{{0}^{-\text{2}}}\text{ }\Omega \]
C) \[\text{3}.\text{14}\times \text{1}{{0}^{-\text{2}}}\text{ }\Omega \]
D) \[\text{2}.\text{2}\times \text{1}{{0}^{-\text{2}}}\text{ }\Omega .\]
E) none of the above
Correct Answer: E
Solution :
Given, \[l=314\,m\] \[\rho =2.2\times {{10}^{-8}}\Omega m\] \[{{D}_{1}}=1.2\times {{10}^{-2}}m\] \[{{D}_{2}}=1\times {{10}^{-2}}m\] As \[R=\frac{\rho l}{A}\] or \[R=\frac{\rho l}{\frac{\pi }{4}[D_{1}^{2}-D_{2}^{2}]}\] or \[R=\frac{4\times 2.2\times {{10}^{-8}}\times 314}{\pi {{[1.2)}^{2}}-{{(1.0)}^{2}}]\times {{10}^{-4}}}\] \[=0.2\,\Omega \]
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