A) \[\text{6}\times \text{l}{{\text{0}}^{\text{-28}}}\]
B) \[\text{6}\times \text{l}{{\text{0}}^{\text{-23}}}\]
C) \[4\times \text{l}{{\text{0}}^{\text{-10}}}\]
D) \[\text{4}\times \text{l}{{0}^{-\text{4}}}\]
E) none of the above
Correct Answer: E
Solution :
The volume of an oxygen molecule has been taken as 2 times that of one oxygen atom In 22.4 L ie \[22.4\times {{10}^{-3}}{{m}^{3}}\] their are \[{{N}_{A}}=6.23\times {{10}^{23}}\] molecules Total volume of oxygen molecules \[=2\times \frac{4}{3}\pi {{r}^{3}}\times {{N}_{A}}\] \[22.4\times {{10}^{-3}}{{m}^{3}}\] is occupied by \[{{N}_{A}}\] molecules. \[\therefore \] Fraction of volume occupied \[=\frac{2\times \frac{4}{3}\pi {{(1.5\times {{10}^{-10}})}^{3}}\times 6.2\times {{10}^{23}}}{(22.4\times {{10}^{-3}})}\] \[=8\times {{10}^{-4}}\]
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