A) \[C{{H}_{3}}-C{{H}_{2}}-CHO\]
B) \[C{{H}_{3}}=CH-C{{H}_{2}}OH\]
C) \[C{{H}_{3}}=CO-C{{H}_{3}}\]
D) \[C{{H}_{2}}=CH-O-C{{H}_{3}}\]
Correct Answer: D
Solution :
Since, the compound does not give a precipitate with 2, 4-dinitrophenylhydrazine, it cannot be an aldehyde or a ketone. Further since it does not react with metallic sodium, therefore, it cannot be an alcohol. Thus, the compound \[{{C}_{3}}{{H}_{6}}O\] must be an ether.
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