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AMU Medical AMU Solved Paper-2008

  • question_answer
    Moment of inertia of circular loop of radius R about the axis of rotation parallel to horizontal diameter at a distance R/2 from it is

    A) \[\text{M}{{\text{R}}^{\text{2}}}\]                                         

    B)  \[\frac{1}{2}\text{M}{{\text{R}}^{\text{2}}}\]

    C) \[\text{2M}{{\text{R}}^{\text{2}}}\]                                      

    D)  \[\frac{3}{4}\text{M}{{\text{R}}^{\text{2}}}\]

    Correct Answer: D

    Solution :

                     Applying theorem of parallel axis                 \[I={{I}_{CM}}+M{{\left( \frac{R}{2} \right)}^{2}}\]                 \[I=\frac{1}{2}M{{R}^{2}}+\frac{M{{R}^{2}}}{4}\]                 \[I=\frac{3}{4}M{{R}^{2}}\]


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