A) ethyl formate
B) ethyl chloroformate
C) acetyl chloride
D) carbon dioxide
Correct Answer: B
Solution :
Ethyl acetate is obtained when methyl magnesium bromide reacts with ethyl chloro for mate. \[C{{H}_{3}}MgBr+Cl-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-O-{{C}_{2}}{{H}_{5}}\] \[\xrightarrow{{}}\left[ Cl-\overset{\begin{smallmatrix} OMgBr \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \\ \downarrow \end{smallmatrix}}{\mathop{C}}\,}}\,-O-{{C}_{2}}{{H}_{5}} \right]\] \[\underset{ethyl\text{ }acetate}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-O-{{C}_{2}}{{H}_{5}}}}\,+MgBrCl\]
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