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AMU Medical AMU Solved Paper-2008

  • question_answer
    A capacitor of capacitance \[C\]has charge \[\text{Q}\]and stored energy is W. If the charge is increased to 2Q, the stored energy will be

    A)  \[\frac{W}{4}\]                                

    B)  \[\frac{W}{2}\]

    C)  2 W                                      

    D)  4 W

    Correct Answer: D

    Solution :

                     From the formula,                 \[W=\frac{{{Q}^{2}}}{2C}\]          ... (i)                 \[W=\frac{{{(2Q)}^{2}}}{2C}\]    \[(\because \,\,\,Q=2Q)\] \[\Rightarrow \]               \[W=4\frac{{{Q}^{2}}}{2C}\] \[\Rightarrow \]               W = 4 W               [From Eq. (i)]


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