question_answer

At low temperature, phenol reacts with \[B{{r}_{2}}\] in \[C{{S}_{2}}\] to form

A)  m-bromophenol

B)  o-and p-bromophenol

C)  p-bromophenol

D)  2, 4, 6-tribromophenol

Correct Answer: B

Solution :

                            In presence of non-polar solvent \[(C{{S}_{2}})\] the ionisation of phenol is suppressed. The ring is slightly activated and hence, mono substitution occurs. On the other hand with Br^ water phenol gives 2, 4, 6-tribromo phenol.