A) \[C{{H}_{3}}-CHOH-C{{H}_{2}}-C{{H}_{3}}\]
B) \[{{(C{{H}_{3}})}_{3}}-C-OH\]
C) \[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}}-OH\]
D) \[{{(C{{H}_{3}})}_{2}}-CH-C{{H}_{2}}OH\]
Correct Answer: B
Solution :
Tertiary alcohol readily reacts with halogen acid. \[C{{H}_{3}}-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{{{C}_{{{3}^{o}}}}}}\,}}\,-OH\xrightarrow{{}}C{{H}_{3}}-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \\ carbonium\text{ }ion \end{smallmatrix}}{\mathop{{{C}^{+}}}}\,}}\,+O{{H}^{-}}\] Presence of 3 alkyl group increases electron density on \[{{3}^{o}}\] carbon atom. Hence, ?OH group is easily removed. After removal of ?OH group \[{{3}^{o}}\] carbonium ion is formed which is most stable.
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