A) carbonium ion intermediate
B) carbene intermediate
C) carbanion intermediate
D) free radical intermediate
Correct Answer: B
Solution :
Reimer-Tiemann reaction involves a carbene intermediate.
\[\overset{\Theta }{\mathop{C}}\,C{{l}_{3}}\xrightarrow{{}}C{{l}^{-}}+\,\,\,\underset{carbene\text{ }intermediate}{\mathop{:CC{{l}_{2}}}}\,\] 
You need to login to perform this action.
You will be redirected in
3 sec
