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AMU Medical AMU Solved Paper-2007

  • question_answer
    The atomic weight of Al is 27. When a current of 5 F is passed through a solution of \[A{{l}^{3+}}\]ions, the weight of Al deposited is

    A)  27 g                                      

    B)  36 g

    C)  45 g                                      

    D)  39 g

    Correct Answer: C

    Solution :

                     \[A{{l}^{3+}}+3{{e}^{-}}\xrightarrow{{}}Al\] Equivalent weight of Al                 \[=\frac{atomic\text{ }weight\text{ }of\text{ }Al}{3}=\frac{27}{3}=9\] Weight of Al = equivalent weight of Al                                 \[\times \] number of Faradays                 \[=9\times 5=45\,g\]


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