A) \[8\times {{10}^{-3}}\]
B) \[8\times {{10}^{-6}}\]
C) \[6.4\times {{10}^{-5}}\]
D) \[6.4\times {{10}^{-3}}\]
Correct Answer: A
Solution :
\[HgS{{O}_{4}}H{{g}^{2+}}SO_{4}^{2-}\] Suppose, solubility of \[HgS{{O}_{4}}\] is S, then Solubility product \[({{K}_{sp}})=S\times S={{S}^{2}}\] Solubility \[=\sqrt{solubility\text{ }product}\] \[=\sqrt{6.4\times {{10}^{-5}}}\] \[=8\times {{10}^{-3}}mol/L\]
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