AMU Medical AMU Solved Paper-2007

  • question_answer
    If \[{{K}_{c}}\] is the equilibrium constant for the formation of \[N{{H}_{3}}\]. The dissociation constant of ammonia under the same temperature will be

    A)  \[{{K}_{c}}\]                                     

    B)  \[\sqrt{{{K}_{c}}}\]

    C)  \[K_{c}^{2}\]                                    

    D)  \[\frac{1}{{{K}_{c}}}\]

    Correct Answer: D

    Solution :

                     \[N{{H}_{3}}\frac{1}{2}{{N}_{2}}+\frac{3}{2}{{H}_{2}}\]                 \[{{K}_{c}}=\frac{{{[{{N}_{2}}]}^{1/2}}{{[{{H}_{2}}]}^{3/2}}}{[N{{H}_{3}}]}\]          ?. (i) \[\frac{1}{2}{{N}_{2}}+\frac{3}{2}{{H}_{2}}N{{H}_{3}}\]                 \[K{{}_{c}}=\frac{[N{{H}_{3}}]}{{{[{{N}_{2}}]}^{1/2}}{{[{{H}_{2}}]}^{3/2}}}\]          ?. (ii) So, for dissociation \[K=\frac{1}{{{K}_{c}}}\]


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