A) \[C{{I}_{4}}\]
B) \[Ge{{I}_{4}}\]
C) \[Sn{{I}_{4}}\]
D) \[Pb{{I}_{4}}\]
Correct Answer: D
Solution :
\[Pb{{I}_{4}}\] is least stable because of two reasons : (i) Size of iodine is biggest. (ii) + 2 oxidation state of Pb is more stable than + 4 oxidation state because of inert pair effect.
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