A) increases
B) decrease
C) becomes zero
D) does not change
Correct Answer: A
Solution :
s-character increases with increase in bond angle.| Hybridisation | % of s character | Bond angle |
| Sp | 50 | \[{{180}^{o}}\] |
| \[s{{p}^{2}}\] | 33.3 | \[{{120}^{o}}\] |
| \[s{{p}^{3}}\] | 25 | \[{{109.28}^{o}}\] |
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