A) 1m/s
B) 10 m/s
C) 100 m/s
D) 0.1 m/s
Correct Answer: B
Solution :
\[{{p}_{1}}+\frac{1}{2}\rho v_{1}^{2}={{p}_{2}}+\frac{1}{2}\rho v_{2}^{2}\] \[\Rightarrow \] \[\frac{1}{2}\rho v_{2}^{2}=({{p}_{1}}-{{p}_{2}})+\frac{1}{2}\rho v_{1}^{2}\] \[=({{p}_{1}}-{{p}_{2}})\] \[(\because {{v}_{1}}=0)\] \[\Rightarrow \] \[{{v}_{2}}=\sqrt{\frac{2({{p}_{1}}-{{p}_{2}})}{\rho }}\] \[\Rightarrow \] \[{{v}_{2}}=\sqrt{\frac{2\times (3.5\times {{10}^{5}}-3\times {{10}^{5}})}{{{10}^{3}}}}\] \[\Rightarrow \] \[{{v}_{2}}=10\,m/s\]
You need to login to perform this action.
You will be redirected in
3 sec
