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AMU Medical AMU Solved Paper-2007

  • question_answer
    Two soap bubbles have radii in the ratio of 2 : 1. What is the ratio of excess pressures inside them?

    A)  1 : 2                                      

    B)  1 : 4

    C)  2 : 1                                      

    D)  4 : 1

    Correct Answer: A

    Solution :

                                    \[p=\frac{4T}{r}\]                 Then,    \[{{p}_{1}}=\frac{4T}{{{r}_{1}}}\] and \[{{P}_{2}}=\frac{4T}{{{r}_{2}}}\] Hence,  \[\frac{{{p}_{1}}}{{{p}_{2}}}=\frac{{{r}_{2}}}{{{r}_{1}}}=\frac{1}{2}\] \[\therefore \]  \[{{p}_{1}}:{{p}_{2}}=1:2\]


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