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AMU Medical AMU Solved Paper-2007

  • question_answer
    A body floats with one-third of its volume outside water and 3/4 of its volume outside another liquid. The density of the other liquid is

    A)  \[\frac{9}{4}g/cc\]                         

    B)  \[\frac{4}{3}g/cc\]

    C)  \[\frac{8}{3}g/cc\]                         

    D)  \[\frac{3}{8}g/cc\]

    Correct Answer: C

    Solution :

                     Let V be volume of the body. In water weight of body                                 = weight of water displaced                                 \[=\frac{2}{3}V\times 1\times g\] In another liquid, weight of body                 \[=\frac{1}{4}\times V\times \rho \times g\] \[\therefore \]  \[\frac{2}{3}Vg=\frac{1}{4}V\rho g\] or            \[\rho =\frac{8}{3}g/cc\]


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