A) \[\text{2}.\text{5}\times \text{1}{{0}^{12}}\]
B) \[\text{2}.\text{5}\times \text{1}{{0}^{11}}\]
C) \[\text{2}.\text{5}\times \text{1}{{0}^{10}}\]
D) \[\text{2}.\text{5}\times \text{1}{{0}^{9}}\]
Correct Answer: B
Solution :
According to Plancks quantitation law, \[E=nhv=n\left( \frac{hc}{\lambda } \right)\] \[\Rightarrow \] \[\frac{E}{t}=\left( \frac{n}{l} \right)\,\left( \frac{hc}{\lambda } \right)\] \[\Rightarrow \] \[{{10}^{-7}}=\left( \frac{n}{t} \right)\frac{6.626\times {{10}^{-34}}\times 3\times {{10}^{8}}}{5000\times {{10}^{-10}}}\] \[\Rightarrow \] \[\frac{n}{t}=\frac{5000\times {{10}^{-10}}\times {{10}^{-7}}}{6.626\times {{10}^{-34}}\times 3\times {{10}^{8}}}\] \[\Rightarrow \] \[\frac{n}{t}=2.5\times {{10}^{11}}s\]
You need to login to perform this action.
You will be redirected in
3 sec
