A) 1A
B) 2 A
C) 4 A
D) 8 A
Correct Answer: D
Solution :
From the formula \[B={{\mu }_{0}}n\,I\] \[\Rightarrow \] \[20\times {{10}^{-3}}=4\pi \times {{10}^{-7}}\times 2000\times I\] \[\therefore \] \[I=\frac{20\times {{10}^{-3}}}{4\pi \times {{10}^{-7}}\times 2000}\] \[\Rightarrow \] \[I\approx 8\,A\]
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