A) increases by 9%
B) decreases by 9 %
C) increases by 11%
D) decreases by 11%
Correct Answer: C
Solution :
\[s={{T}_{descent}}=\frac{u\sin \alpha }{g}\] \[T=\frac{u\sin \alpha }{g-\frac{g}{10}}=\frac{10}{9}\left( \frac{u\sin \alpha }{g} \right)\] So, increase in time is \[\left( \frac{10}{9}-1 \right)T\] \[\Rightarrow \] percent increase \[=\frac{100}{9}=11%\]
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