question_answer

In the figure, the equivalent capacitance between A and B is

A) \[\text{3}.\text{75 }\mu \text{F}\]                         

B)  \[\text{5}.\text{25 }\mu \text{F}\]

C) \[\text{6}.\text{5 }\mu \text{F}\]                            

D)  \[\text{1}0.\text{5 }\mu \text{F}\]

Correct Answer: A

Solution :

                 The circuit can be simplified as shown.                                                 It is a balanced Wheatstone bridge. \[\Rightarrow \]               \[{{C}_{AB}}=\frac{5\times 3}{5+3}+\frac{5\times 3}{5+3}\] \[\Rightarrow \]               \[{{C}_{AB}}=2\times \frac{15}{8}\]                                 \[=\frac{30}{8}=3.75\,\mu F\]