A) \[\overset{\to }{\mathop{\text{a}}}\,\ne \overset{\to }{\mathop{\text{b}}}\,\]
B) \[\overset{\to }{\mathop{\text{a}}}\,.\overset{\to }{\mathop{\text{b}}}\,=0\]
C) \[|\overset{\to }{\mathop{\text{a}}}\,|=|\overset{\to }{\mathop{\text{b}}}\,|\]
D) \[\overset{\to }{\mathop{\text{a}}}\,.\overset{\to }{\mathop{\text{b}}}\,=1\]
Correct Answer: C
Solution :
\[(\vec{a}+\vec{b})\,.\,\,(\vec{a}-\vec{b})=0\] \[\Rightarrow \] \[{{a}^{2}}-{{b}^{2}}=0\] \[\Rightarrow \] \[\left| {\vec{a}} \right|=\left| {\vec{b}} \right|\]
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