A) zero
B) 0.2 m
C) 0.4 m
D) 0.8 m
Correct Answer: B
Solution :
From first equation of motion \[v=u+at\] \[0=4+a\times (0.1)\] \[\Rightarrow \] \[a=-40\,\,m/{{s}^{2}}\] (declaration) \[\therefore \] \[s=\frac{{{u}^{2}}}{2\,a}\] \[\Rightarrow \] \[s=\frac{{{(4)}^{2}}}{2\times 40}\] \[\Rightarrow \] \[s=\frac{16}{80}\] \[\Rightarrow \] s = 0.2 m
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