A) 10 MeV
B) 1 keV
C) 0.1 MeV
D) 0.01 eV
Correct Answer: D
Solution :
\[E=\frac{1}{2}{{k}_{B}}T\] At T = 300 K \[\therefore \] \[E=\frac{1}{2}(1.38\times {{10}^{-23}})\,(300)\] \[\Rightarrow \] \[E=\frac{1}{2}\frac{(1.38\times {{10}^{-23}})\,(300)}{(1.6\times {{10}^{-19}})}eV\] \[\Rightarrow \] E = 0.01 eV
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