A) 4.5\[\Omega \]
B) 12\[\Omega \]
C) 5.4\[\Omega \]
D) 20\[\Omega \]
Correct Answer: A
Solution :
\[7\,\Omega ,\,\,3\,\Omega \] are in parallel and \[6\,\Omega ,\,\,4\,\Omega \] are in parallel and both combinations are in series. So, \[{{R}_{eq}}=\frac{7\times 3}{7+3}+\frac{4\times 6}{4+6}\] \[\Rightarrow \] \[{{R}_{eq}}=\frac{21}{10}+\frac{24}{10}\] \[\Rightarrow \] \[{{R}_{eq}}=2.1+2.4\] \[\Rightarrow \] \[{{R}_{eq}}=4.5\,\Omega \]
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