AMU Medical AMU Solved Paper-2006

  • question_answer
    In the electrolysis of water, one faraday of electrical energy would evolve

    A)  one mole of oxygen

    B)  one g atom of oxygen

    C)  8 g of oxygen

    D)  22.4 L of oxygen

    Correct Answer: C

    Solution :

                     Hydrolysis of water can be represented by the following equations                 \[2{{H}_{2}}O{{O}_{2}}+4{{H}^{+}}+4{{e}^{-}}\] \[\because \] 4 faraday of charge liberate \[{{O}_{2}}=32\,g\] \[\therefore \] 1 faraday of charge liberate \[{{O}_{2}}=\frac{32}{4}=8\,g\]


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