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AMU Medical AMU Solved Paper-2006

  • question_answer
    The magnetic force on a point charge is \[\overset{\to }{\mathop{F}}\,=q(\overset{\to }{\mathop{V}}\,\times \overset{\to }{\mathop{B}}\,)\] Here, q = electric charge \[\overset{\to }{\mathop{V}}\,\]= velocity of point charge \[\overset{\to }{\mathop{B}}\,\]= magnetic field The dimension of \[\overset{\to }{\mathop{B}}\,\]is

    A) \[\left[ \text{ML}{{\text{T}}^{-1}}\text{A} \right]\]         

    B)  \[\left[ {{\text{M}}^{2}}\text{L}{{\text{T}}^{-2}}{{\text{T}}^{-1}} \right]\]

    C) \[\left[ \text{M}{{\text{T}}^{-2}}{{A}^{-1}} \right]\]        

    D)  None of these

    Correct Answer: C

    Solution :

                     \[\vec{F}=q\,\vec{v}\times \vec{B}\] or            \[F=q\,v\,B\sin \theta \] \[\therefore \]  \[[B]=\left[ \frac{F}{qv} \right]=\frac{[ML{{T}^{-2}}]}{[AT][L{{T}^{-1}}]}\]                                 \[=\,[M{{T}^{-2}}{{A}^{-1}}]\]


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