question_answer

Number of isomers possible for \[{{C}_{4}}{{H}_{8}}O\] is

A)  3                            

B)  4

C)   5                                           

D)  6

Correct Answer: D

Solution :

                 There are 6 isomers possible for the compounds having molecular formula \[{{C}_{4}}{{H}_{8}}O\], which are as follows : \[C{{H}_{3}}C{{H}_{2}}\overset{\begin{smallmatrix}  O \\  || \end{smallmatrix}}{\mathop{\underset{(i)}{\mathop{C}}\,}}\,-C{{H}_{3}}\],                \[\underset{(ii)}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CHO}}\,\]                                 and        \[\underset{(vi)}{\mathop{C{{H}_{2}}=CH-C{{H}_{2}}C{{H}_{2}}OH}}\,\]