AMU Medical AMU Solved Paper-2006

  • question_answer
    If the de-Broglie wavelength of a proton is \[\text{1}{{0}^{-\text{13}}}\text{ m},\]the electric potential through which it must have been accelerated is

    A) \[\text{4}.0\text{7}\times \text{1}{{0}^{\text{4}}}\text{ V}\]     

    B)  \[\text{8}.\text{2}\times \text{1}{{0}^{\text{4}}}\text{ V}\]

    C) \[\text{8}.\text{2}\times \text{1}{{0}^{\text{3}}}\text{ V}\]                       

    D)  \[\text{4}.0\text{7}\times \text{1}{{0}^{\text{5}}}\text{ V}\]

    Correct Answer: B

    Solution :

                     \[\lambda =\frac{h}{\sqrt{2\,mqV}}\] \[{{({{10}^{-13}})}^{2}}=\frac{{{(6.6\times {{10}^{-34}})}^{2}}}{2\times 1.67\times {{10}^{-27}}\times 1.6\times {{10}^{-19}}V}\]                 \[v=8.2\times {{10}^{4}}\] volt


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