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AMU Medical AMU Solved Paper-2006

  • question_answer
    In a Youngs experiment, one of the slit is covered with a transparent sheet of thickness \[\text{3}.\text{6}\times \text{1}{{\text{0}}^{-3}}\text{ cm}\]due to which position of central fringe shifts to a position originally occupied by 30th bright fringe. The refractive index of the sheet, if K = 6000 Å is

    A)  1.5                                        

    B)  1.2

    C)  1.3                                        

    D)  1.7

    Correct Answer: A

    Solution :

                     The position of 30th bright fringe                 \[{{y}_{30}}=\frac{30\lambda D}{d}\] Now, position shift to central fringe is                 \[{{y}_{0}}=\frac{30\lambda D}{d}\] But we know \[{{y}_{0}}=\frac{D}{d}\,(\mu -1)\,t\]                 \[\frac{30\lambda D}{d}=\frac{D}{d}\,(\mu -1)\,t\]                 \[(\mu -1)=\frac{30\lambda }{t}\]                 \[=\frac{30\times 6000\times {{10}^{-10}}}{3.6\times {{10}^{-5}}}=0.5\]                 \[\mu =1.5\]


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